fie x=ziua1, y=ziua2, z=ziua3, t=totalul
x+y+z=t
[tex]x= \frac{t}{4}+60[/tex][tex]y= \frac{x}{4}+30= \frac{ \frac{t}{4}+60 }{4}+30= \frac{t}16} +15+30= [/tex]
[tex]z= \frac{y}{3} +10= \frac{\frac{t}{16}+45}{3}+10= \frac{t}{48} +25+10= \frac{t}{48}+35 [/tex]
x+y+z=t
[tex] \frac{t}{4} + \frac{t}{16} + \frac{t}{48} +60+45+25=t[/tex]
[tex] \frac{12t+3t+t}{48} +130=t[/tex]
[tex]130= \frac{(48-16)*t}{48} [/tex]
[tex]\frac{2t}{3}=130[/tex]
t=490/2=245
