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stiind ca 4a+b/3a-b=4, aflati a/b

Răspuns :

[tex] \frac{a}{b} =k [/tex]   ⇒  a=kb

[tex] \frac{4a+b}{3a-b} = \frac{4kb+b}{3kb-b} = \frac{b(4k+1)}{b(3k-1)} =4[/tex]

⇒4k+1=4(3k-1)  ⇒   4k+1=12k-4   |scad 4k din ambii membrii ai egalitatii ⇒4k-4k+1=12k-4k-4  ⇒1=8k-4   | adun 4  ⇒1+4=8k+4-4  ⇒5=8k  ⇒k=[tex] \frac{5}{8} [/tex]