P+G+M+T = 111 ani
P = G+3
P = M:4 => M = 4×P
T = M+4
P |___|+3
G |___|
M |___|___|___|___|+12
T |___|___|___|___|+4+12
avem 10 segmente egale +3+12+4+12 = 111
111-(3+12+4+12) =111-31 = 80
80 : 10 = 8 ( un segment egal)
P = 8+3 = 11
G = 8
M = 4×8+12 = 32+12 = 44
T = 4×8+4+12 = 32+16 = 48
Verificare:
11+8+44+48 = 111
Patricia 11 ani
George 8 ani
mama 44 ani
tata 48 ani