4mol..............................1mol
MnO2 +4HCl----> MnCl2 +2H2O+Cl2
6mol...................................x= 6/4= 1,5mol Cl2
M,KClO3=122,5g/mol
n= m/M--->n=0,5mol
1mol...............................................3mol
KClO3 + 6HCl ===> KCl + 3H2O+3Cl2
0,5mol.................................................x= 1,5mol Cl2
m= nxM----> m= 1,5molx71g/mol=................................
V=nxVm---> V= 1,5molx22,4l/mol=..........................calculeaza !!!!!