a+b+c = 3 333
b = 3×a:2 |×2
2×b= 3×a
c = 2×b
a |___|___|
b |___|___|___|
c |___|___|___|___|___|___|
avem 11 segmente egale = 3 333
3 333 :11 = 303 ( un segment egal)
a = 2×303 = 606
b = 3×303 = 909
c = 6×303 = 1 818
Verificare:
606+909+1 818 = 3 333
909 = 3×606:2
909 = 3×303
909 = 909
a = 606
b = 909
c = 1 818
