a+b+c = 172
a:b = 2 rest 6
a = 2×b+6
b:c = 3 rest 12
b = 3×c+12
a |____|____|____|____|____|____|+24+6
b |____|____|____|+12
c |____|
avem 10 segmente egale +30+12 = 172
172-(30+12) = 172-42 = 130
130 : 10 = 13 ( un segment )
a = 6×13 +30 = 78+30 = 108
b = 3×13+12 = 39+12 = 51
c = 13
Verificare:
108+51+13 = 172
a = 108
b = 51
c = 13