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lg x2 + 5 = lg9 va rogggggggggggggg

Răspuns :

Ecuati se poate scrie : [tex]lgx^2=lg9-5,sau,lgx^2=lg9-lg10^5,restrangem,lgx^2=lg \frac{9}{10^5} [/tex], adica: [tex] x^{2} = \frac{9}{10^5},deci, x_{1,2}=+sau- \sqrt{ \frac{9}{10^5} },adica, x_{1}=- \frac{3}{100}* \frac{1}{ \sqrt{10} },si, [/tex][tex]x_{2}= \frac{3}{100}* \frac{1}{ \sqrt{10} }. [/tex]