triunghiul ΔNMP ∡ N drept este dreptunghic
NM= 3 (u) 1u =0,5 cm
NP=2 (u)
PM²=MN²+NP² (t. Pitagora)
PM²=3²+2²=13
PM=√13
a) sin M=PN/PM=2/√13=2√13/13 ( am rationalizat amplificand cu √13)
b(cos M=MN/PM=3/√13=3√13/13
c) tg P=MN/NP=3/2
d) ctg P = NP/MN=2/3 (sau = 1/tg P= cos P / sin P)