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Calculati suma a 25 de numere naturale consecutive stiind ca primul si al patrulea numar sunt direct proportionale cu numerele 4 si 5.

Răspuns :

[tex]\mathtt{a_1+a_2+a_3+...+a_{25}=x}[/tex]

[tex]\mathtt{a+(a+1)+(a+2)+...+(a+24)=x}[/tex]

[tex]\mathtt{\frac{a}{4}=\frac{a+3}{5}=k}[/tex]

[tex]\mathtt{a=4k}[/tex]

[tex]\mathtt{a+3=5k=\textgreater a=5k-3}[/tex]

[tex]\mathtt{4k=5k-3}[/tex]

[tex]\mathtt{k=3}[/tex]

[tex]\mathtt{a=4\cdot3=12}[/tex]

[tex]\mathtt{x=12+13+14+...+36}[/tex]

[tex]\mathtt{x=36+35+34+...+12}[/tex]

[tex]\mathtt{2x=48+48+48+...+48}[/tex]
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                          25 de termeni

[tex]\mathtt{2x=25\cdot48}[/tex]

[tex]\mathtt{x=\frac{25\cdot48}{2}=600}[/tex]