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rezolvati in r ecuatia (2x la puterea a 2 -5x)(7x+1)=0

Răspuns :

[tex](2x^2-5x)(7x+1)=0[/tex]
[tex]x(2x-5)(7x+1)=0[/tex]

[tex]x_1 = 0[/tex]
[tex]2x-5 = 0 =\ \textgreater \ x_2 = \frac{5}{2} [/tex]
[tex]7x+1=0 =\ \textgreater \ x_3 = - \frac{1}{7} [/tex]