a+b+c = 1 018
b = a:4 => a = 4×b
a = c-37 => c = a+37
a |___|___|___|___|
b |___|
c |___|___|___|___|+37
avem 9 segmente egale +37 = 1 018
1 018 - 37 = 981
981 : 9 = 109 ( un segment egal)
a = 4×109 = 436
b = 109
c = 4×109+37 = 436+37 = 473
Verificare:
436 + 109 + 473 = 1 018
a = 436
b = 109
c = 473