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scrieti sub forma de raport algebric ireductibil:

3a+2 4+6a
-------- : --------
a-√3 5a²-15


Răspuns :

(3a+2)/(a-√3) :(4+6a)/(5a²-15)=
=(3a+2)/(a-√3) ×5(a²-3)/ 2(2+3a)=
=1/(a-√3) ×5(a-√3)(a+√3)/ 2=
=5(a-√3)/ 2