x si y partile
x+y=6
a) {x;y} invers prop. {2,3} la numitor inversele lui 2 si 3
[tex] \frac{x}{ \frac{1}{2} }= \frac{y}{ \frac{1}{3} } = \frac{x+y}{ \frac{1}{2} + \frac{1}{3} } = \frac{6}{ \frac{3+2}{6} } =6: \frac{5}{6} = \frac{36}{5} [/tex]
[tex] \frac{x}{ \frac{1}{2} } = \frac{36}{5} [/tex] ⇒ x=36/10 =3,6
3,6+y=6 ⇒y= 2,4
b) [tex] \frac{x}{2} = \frac{y}{3} = \frac{x+y}{2+3} = \frac{6}{5} [/tex]
si mai departe ca la a)
