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care este concentratia procentuala a solutiei obtinuta prin amestecarea a 250g solutie HCL 20% cu 250g solutie HCL 40%?



Răspuns :

ms1= 250 g solutie HCl
c1= 20%
md1=( 20*250):100= 50 g HCl
ms2= 250 g solutie HCl
c2= 40%
md2=(40*250):100= 100 g HCl
md final= md1 + md2= 150 g HCl
ms final= ms1+ ms2= 500 g solutie
c final = (150*100):500= 30%