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Daca x/ y=3/5 aflati
5xy/2y^2-x^2 =; 5x^3 -y^3/y ^3-3x ^3=;


Răspuns :

x=3y/5
inlocuim si simplificam
(5·3y/5·y)/(2y²- 9y²/25)=3y²/(16y²/25)=3y²:16y²/25=3y²·25/16y²=75/16
(5·27y³/125-y³)/(y³-3·27y³/125)= (27y³/25-y³)/(y³-81y³/125)=
=(2y³/25)/(44y³/125)=2y³/25:44y³/125=2y³/25·125/44y³=5/22