a+a+1+a+2 = 132
3×a+3 = 132
3×a = 132-3
3×a = 129
a = 129:3
a = 43
Verificare:
43+44+45 = 132
Numerele consecutive sunt:
43; 44; 45
sau
a |____|
b |____|+1
c |____|+2
3 segmente egale +1+2 = 132
132 -3 = 129
129 : 3 = 43 ( un segment)
a = 43
b = 43+1 = 44
c = 43+2 = 45