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Determinati solutile intregi ale ecuatiei 5x la 2 -3x-8=o

Răspuns :

5x²-3x-8=0
a=5, b=(-3), c=(-8)
Δ=9-4·5·(-8)
Δ=9+160
Δ=169 =>√Δ=13
x₁=(3-13)/10=(-1)
x₂=(3+13)/10=16/10=1,6
[tex]5x^2-3x-8=0 \\ \\ 5x^2+5x-8x-8=0 \\ \\ 5x(x+1)-8(x+1)=0 \\ \\ (x+1)(5x-8)=0 \\ \\ x+1=0=\textgreater x=-1 \\ \\ 5x-8=0=\textgreater x=\frac{8}{5}[/tex]