E problema de liceu sunt Gimnzaiu si o fac :))
{x,y}d.p{3,4}
[tex] x^{2} + y^{2} = 625
[/tex]
[tex] \frac{x}{3}= \frac{y}{4} [/tex]
x=[tex]x= \frac{3y}{4} [/tex]
[tex] (\frac{3y}{4})^{2} + y^{2} =625[/tex][tex] \frac{9 y^{2}}{16} + \frac{16 y^{2} }{16} =625
[/tex][tex] \frac{25 y^{2} }{16}=625=\ \textgreater \ y^{2} = \frac{625*16}{25} =25*16[/tex]
[tex] y=20 [/tex]
x=(3*20)4
x=15
