r+a=126
v+a=95
v+r=143
adun cele 3 relatii membru cu membru si obtin
2r+2a+2v=126+95+143
2*(a+v+r)=364
r+a+v=364:2
r+a+v=182 dar r+a=126
inlocuiesc si obtin 126+v=182, v=182-126, v= 56
dar a+v=95 rezulta a+56=95, a=95-56, a=39
r+a=126, r+39=126, r=126-39, r=87