[tex]x-2y=10 | totul^{2} --\ \textgreater \
(x-2y)^{2} = 10^{2} --\ \textgreater \
x^{2} +4y^{2} -4xy=100[/tex] ,iar [tex] x^{2} +4y ^{2} =52 --\ \textgreater \ -4xy=100-52=48--\ \textgreater \ xy=-12[/tex] si apoi [tex]( x+2y)^{2} = x^{2} +4xy +4y ^{2} =52-48=4--\ \textgreater \ x+2y=2[/tex] ,dupa din x-2y=10 aduni x+2y=2 si tit iese 2x=12 adica x=6 ,iar y iti da -2 .Cred ca e bine,daca nu ,imi pare rau
