a+b+c = 382
b = a:2 => a = 2b
b : c = 3 rest 4
b = 3c+4 => c = (b-4)/3
inlocuim in prima ecuatie in functie de b
2b+b+(b-4)/3 = 382 |×3
6b+3b+b-4 = 1 146
10b = 1 146+4
10b = 1 150 |:10
b = 115
a = 2×115 = 230
c = (115-4)/3 = 111:3 = 37
Verificare:
230+115+37 = 382
a = 230
b = 115
c = 37