solutia NaOH : Vs1 [HO⁻]= 10⁻² nHO⁻ = 10⁻²ₓVs1
solutia de HNO3 : Vs2 [H⁺] = 10⁻² nH⁺ = 10⁻²ₓVs2
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solutia finala : Vs = Vs1 + Vs2 = 10⁻² l [H⁺]exces = 10⁻³
nH⁺ exces =10⁻⁵moli
(NaOH reactioneaza in intregime)
10⁻²Vs2 - 10⁻²Vs1 = 10⁻⁵ Vs2 - Vs1 = 1o⁻³ l = 1 ml
Vs2 + Vs1 = 10ml 2Vs2 = 11ml
Vs2 = 5,5 ml acid
Vs1 = 4,5ml baza
A ) F B) F C) : F D): A E) : A
Vs1/Vs2 = 4,5/5,5 = 9/11
