-calculez masa de alcool din 1kg solutie(1000g)
c= mdx100/ms
30/100=md/1000-----> md= 300g alcool(2propanol); M,C3H8O= 60g/mol
n(niu)=300g/60g/mol= 5mol
- din ecuatia reactiei, deduc moli propena
1mol....................................1mol
CH2=CH-CH3+HOH---> CH3-CHOH-CH3
x=5............................................5mol
n=5 mol propena este valoarea teoretica; practic, trebuie sa se ia mai multi moli, pentru ca in timpul reactiei au loc pierderi
n,practic= 5x100/80mol= 6,25mol propena
V=nxVm
V=6,25molx22,4l/mol=........................calculeaza !!!!