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sa se rezolve ecuatia
1 + 2sin3x = 0


Răspuns :

2sin3x=-1
sin3x=-1/2
3x=kπ+ (-1)^k arcsin(-1/2)
3x=kπ+(-1)^k*(-π/6)
x=kπ/3+(-1)^k* (-π/18)
sau
x=kπ/3+(-1)^(k+1)*(π/18)