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sa se rezolve ecuatia

[tex] \sqrt{3} + 2sinx = 0[/tex]


Răspuns :

2sinx=-√3
sinx=-√3/2
x=kπ+(-1)^k*arcsin(-√3/2)
x=kπ+(-1)^k* (-π/3)
x=kπ+ (-1)^(k+1)*(π/3)