a-bile albe
b-bile rosii
c-bile negre
a+b+c=49
a=2×b =>a=2×c×2
c=b:2 => b=c×2
a) |---|---|---|---|
b) |---|---|
c) |---| } acolada toate trei 49
Avem 7 segmente egale
49:7=7 (c) bile negre
7×2=14 (b) bile rosii
(7×2)×2=14×2=28 (a) bile albe
proba
28+14+7=42+7=49 (Adevarat )