m+ c + g = 110
g = c : 3 => c = 3×g
c = m - 12 => m = c + 12
m |____|____|____|+12
c |____|____|____|
g |____|
avem 7 segmente egale +12 = 110
110 - 12 = 98
98 : 7 = 14 (un segment egal)
m = 3×14+12 = 42+12 = 54
c = 3×14 = 42
g = 14
Verificare:
54 + 42 + 14 = 110
54 lazi cu mere
42 lazi cu caise
14 lazi cu gutui