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Rezolva prin metoda substitutiei sistemele :
a) 3(x-1) + 2(y+4) = 24
3(y+1) + x la puterea a 2 a = (x+1) (x-1) -2x

b)) 3(x+3)-2(y+5)=1
(X+3)(y-5)=x(y-7) +8


Răspuns :

3(x-1)+2(y+4)=24
3x-3+2y+8=24
3x+5+2y=24
3x=24-5-2y
3x=19-2y
x=19 supra 3 - 2supra 3 y

3(y+1)+x2=(x+1)*(x-1)-2x
3y+3+x2=x2-1-2x
3y+3 = -1-2x
3y = -1-2x-3
3y = -4-2x
y = -4 supra 3 - 2 supra 3 x

x2 inseamna x la 2