a + b + c = 1 012
b = a : 2 + 40
c = 3×a
a |____|____|
b |____|+40
c |____|____|____|____|____|____|
avem 9 segmente egale +40 = 1 012
1 012 - 40 = 972
972 : 9 = 108 (un segment egal)
a = 2 × 108 = 216
b = 108 × 40 = 148
c = 6×108 = 648
Verificare:
216+148+648 = 1 012
148 = 216:2+40
148 = 108+40
148 = 148
a = 216
b = 148
c = 648