Acid : CxH(2x-2)O4 M acid = 14x +62
Anhidrida : CxH(2x-4)O3 M anhidrida = 14x + 44 = M
anhidrida + H2O ⇒ acid
n anhidrida =4,9/M = n acid
HOOC- [CH2](x-2) - COOH + 2NaOH ⇒ NaOOC-[CH2](x-2)-COONa +2H2O
nNaOH = 0,1·40/40 = 0,1 moli = 2n acid ⇒ nacid = 0,05 moli = n anhidrida
M = 4,9/0,05 = 98 g/mol
M acid = 116 g/mol 116 - 2·45 = 26 acid : HOOC-CH=CH-COOH