rezolvare fara folosirea tabelelor trigonometrice
aria ABC=AB*AC sin(A)/2 = BC*AD/2,
AB=AC=l
AD=h
l^2 sin(30)=16h , sin (30)=1/2
l^2=32h (1)
cu pitagora in tr. ABD
l^2=h^2+BD^2=h^2+8^2 (2)
din (1) si (2)
h^2+64=32h
h^2-32h+64=0
h=8(2+√3), cealalta solutie nu ne pasioneaza
l=√32h=√[32*8(2+√3)]
l=16√(2+√3)
AB*CE=BC*h
CE=BC*h/AB=16*8(2+√3)/16√(2+√3)
CE=BF=8√(2+√3)
