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(2x+3)^2 - 3x (1-x)+2 (x-3)-(3x-2)^2

Răspuns :

(2x+3)²-3x(1-x)+2(x-3)-(3x-2)²=
4x²+12x+9-3x+3x²+2x-6-(9x²-12x+4)=
4x²+12x+9-3x+3x²+2x-6-9x²+12x-4=-2x²+23x-1

(2x+3)^2 - 3x (1-x)+2 (x-3)-(3x-2)^2 =
 4x^2 +12x + 9 - 3x + 3x^2 + 2x - 6 -9x^2 +12x - 4 = 
- 2x^2 +23x -1