fie m, povara magarului si c, povara catarului
avemecuatiile
(m+100)=2(c-100)
3(m-100)=c+100
m+100=2c-200
3m-300=c+100
m-2c=-300
3m-c=400
din a doua rellatie c=3m-400
o subsutuim in prima
m-2(3m-400)=-300
m-6m+800=-300
-5m=-1100
5m=1100
m=220
c=3m-400=3*220-400=660-400=260
m=220
c=260
Verificare
220+100=2(260-100).....320=2*160 adevarat
3(220-100)=260+100......3*120=360 adevarat
problema este bine rezolvata