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volumul unui trunchi de piramida triunghiulara regulata cu latura bazei mari de 9 cm latura bazei mici de 6 cm si inaltimea de 2

Răspuns :

V=h/3(A+Ab+√A·Ab)=2/3(81√3/4+36√3/4+27√3)=2/3·225√3/4=75√3/2
Vtr.de pir.=h/3•(AB+Ab+(✓AB•√Ab)=2/3•(81√3/4+9√3+(81√3/4•9√3)=2/3(81√3/4+36√3/4+6/4)=2/3•6+117√3/4=2/1•6+39√3/4=6+39√3/4.