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Plzzz!!!!!! Am nevoie urgent

Plzzz Am Nevoie Urgent class=

Răspuns :

   
[tex]\displaystyle\\ \bf\\ \text{Amplificam cu conjugatul numitorului }\\ ~~~~~~~~~( \sqrt{2}+1 ) \\ \text{pentru a rationaliza numitorul.}\\\\ \texttt{Rezolvare:}\\\\ b= \frac{\sqrt{2}+1 }{\sqrt{2}-1 } = \frac{(\sqrt{2}+1)(\sqrt{2}+1) }{(\sqrt{2}-1)(\sqrt{2}+1) } = \frac{(\sqrt{2}+1)^2 }{2-1 } = \boxed{\bf (\sqrt{2}+1)^2}[/tex]