AC=x
AB=y
AD⊥BC
proiectia AC pe BC=u
proiectia AB pe BC =v
cu teorema catetei obtinem?
x^2=u*BC
y^2=v*BC
x^2/y^2 = u/v=1,(7)=16/9
x/y=4/3
x=4y/3
x+y=105
4y/3+y=105
7y=315
y=45
x=4*45/3
x=60
BC^2=x^2+y^2
BC^2=3600+2025=5625
BC=75
perimetru
P=x+y+BC=60+45+75=180 cm
aria
A=x*y/2=60*45/2=1350 cm2
