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stiind ca xy+yz=320 si x+z=16 aflati numarul natural y

Răspuns :

xy+yz= 320
x+z = 16

y(x+z) = 320
16y = 320
y = 320/16
y = 20

y(x+z)=320
y×16=320
y=320:16
y=20