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descompuneti in factori ireductibili x la a 2 - 12x +27

Răspuns :

X^2-12x+27
Delta= b^2-4ac= 144-108= 252
X1= -b-√ delta supra2= 12-√252 supra 2= 12-6√7 supra 2= 6-3√7
X2= 6+3√7
X^2-12x+27= (x-6+3√7)(x-6-3√7)