A = arena B = arena cu catena laterala saturata ; C = arena cu catena nesaturata;
C : CxH(2x-8) M = 14x - 8 12x = 0,91525(14x-8)
13,11x = 14x - 8 0,88x = 8 x = 9 y = 10 C = C9H10 (αmetilstiren)
⇔B = C9H12(izopropilbenzen) ; A = benzen a = propena
a) amestec : C9H12 n moli M1 = 120g/mol n1C = 9n m1 = 120n
C9H10 n moli M2 = 118g/mol n2C = 9n m2 = 118n
%C = 18n·12·100/(238n) = 90,756%
b) C9H12 : m n1 = m/120 nC = 9n1 = 9m/120 mC = 0,9m
C9H10 m n2 = m/118 nC = 9n2= 9m/118 mC = 0,915m
%C = 1,815m·100/(2m) = 90,762%
