[tex]\displaystyle \\
\text{Rexolvare pentru scoala generala:}\\\\
\sin30^o\cos60^o - \sin60^o\cos30^o = \\\\
= \frac{1}{2}\times \frac{1}{2} - \frac{ \sqrt{3} }{2}\times \frac{ \sqrt{3} }{2}= \frac{1}{4}- \frac{3}{4}= -\frac{2}{4}=\boxed{-\frac{1}{2}}\\\\\\
\text{Rexolvare pentru liceu:}\\\\
\text{Folosim formula: } \sin a\cos b - \cos a \sin b= sin(a-b)\\\\
\text{Rezolvare:}\\\\
\sin30^o\cos60^o - \sin60^o\cos30^o =\\\\
=\sin(30^o - 60^0)= \sin(-30^o)=-\sin30^o = \boxed{-\frac{1}{2}}[/tex]
