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Simplificati raportul : 2x^2+5x-3/2x^2-7x+3 , unde x apartine R - {1/2;3}

Răspuns :

[tex] \frac{2x^2+5x-3}{2x^2-7x+3} = \frac{2x^2+6x-x-3}{2x^2-x-6x+3} =\\  \frac{2x(x+3)-(x+3)}{x(2x-1)-3(2x-1)} =\\ \frac{(x+3)(2x-1)}{(2x-1)(x-3)} =\\ \frac{x+3}{x-3} [/tex]