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rezolvati ecuatile x2+5x+6=0

Răspuns :

delta = b^2-4ac
delta = 5*5 - 4*1*6
delta = 25-24
delta=1

x1 = -b-radical delta / 2a
x1 = -5-1/2*1
x1=-6/2
x1=-3

x2= -b+radical delta / 2a
x2= -5+1/2*1
x2=-4/2
x2=-2