C12H22O11 + H2O = glucoza + fructoza
n zaharoza = 25,65/342 =0,075 moli = n glucoza
C6H12O6 + [O] = C6H12O7 (C5H11O5COOH )
2 glucoza + Ca(OH)2 = (C5H11O5COO)2Ca + 2H2O
n gluconat = 0,8·0,075/2 = 0,03 moli
solutia de gluconat : md = 0,03·430 = 12,9 g ⇒ ms = 12,9·100/10 = 129g
Vs = 129/1,121 = 115 ml
n fiole = 115 : 10 = 11,5 (12)