a) 22,4 L oxigen (1 mol)................6,022*10²³ atomi
2,24 L oxigen ........................... x
x=6,022*10²³/10=6,022*10²² atomi
b) M O2=2*16=32
32 g O2 (1 mol)....................6,022*10²³ molecule
m ...................................1806,6*10²³ molecule
m=9600 g O2