D:I = 3 rest 10
D = 3×I+10
D+I+3+10=143
3×I+10+I+13=143
4×I = 143-23
4×I = 120
I = 120:4
I = 30 (impartitorul)
D = 3×30+10 = 100 (deimpartitul)
verificare:
100:30 = 3 rest 10
100+30+3+10 = 143
100 si 30 sunt cele doua numere
metoda grafica:
D+I = 143-13= 130
D = 3×I + 10
D /---/---/---/+10
I /---/
130-10=120
120:4 = 30 (un segment egal)
D = 3×30+10= 90+10=100
I = 30