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1 Cate grame de NaNO3 contin 28g N?
2 Cati moli dr NH3 contin 9g H2?


Răspuns :

1. M NaNO3=23+14+3*16=23+14+48=85

   85 g NaNO3........14 g N
    m .......................28 g N

 m=85*2=170 g NaNO3

2.M NH3=14+3*1=17

  17 g NH3...........3 g H2
    m ....................9 g H2

m=17*3=51 g NH3