👤

Calculati volumul de solutie de HCl6M ce actioneaza cu 800 g PS2.

Răspuns :

4HCl + PbO₂ ⇒ PbCl+ Cl₂ + 2H2O

2Cl
⁻¹ -2e⁻ ⇒ Cl₂⁰ se oxideaza (ag.red)   ||2|1

Pb⁺⁴ +2e⁻ ⇒ Pb⁺² se reduce (ag.ox)      ||2|1

MPbO₂ = 239g/mol

n = m/M = 800/239 = 3,3472 moli PbO₂

4 moli HCl.............1 mol PbO₂
x = 13,389 moli........3,3472 moli

C = n/Vs => Vs =n/C = 13,389/6 = 2,23152 L sol. HCl