👤

fractia ireductibila 3n+119/2n+79

Răspuns :

[tex]\displaystyle Presupunem~ca~fractia~este~reductibila \\ \implies\exists~ d\neq1~,~d\in N^*~,~astfel~incat: \\ d|3n+119\implies d|2(3n+119)\implies d|238+6n~si \\ d|2n+79\implies d|3(2n+79)\implies d|6n+278 \\ \implies d|(6n+238)-(6n+237)\implies\boxed{d|1} \\ Contradictie!\implies \frac{3n+119}{2n+79}~este~ireductibila \\ \\ Obs:Daca~d|a~si~d|b~atunci~d|a-b[/tex]