Integrala 2 nu e definita in 0
3)I=∫xe^xdx x∈[0,1] Se rezolva prin parti
u=x du =dx
dv=e^xdx=> v=e^x
I=x*e^x-∫e^xdx=x*e^x-e^x)o↑1=(e-e)-(0-e^0)=1
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I=∫dx/(x²+3)=∫dx/(x²+(√3)²)=1/√3*arctgx/√3lo↑1=1/√3arctg1/√3=1/√3arctg0=rationalizezi numitorul fractiilor a,mplificand cu √3=
√3/3*arctg √3/3-0=√3/3*π/6=√3π/18
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f(x)={3^x+2 pt x≥1
{x²+3x+1 x<1
∫(3^x+2)dx=∫3^xdx+2∫dx x∈[2.3]
3^x/ln3+2x) x∈[2,3]
3^x/ln3l 2↑3+(3-2)=3^3/ln3-3^2/ln3+1=(27-9)/ln3+1=18/ln3+1
Aria =∫(3x²+2x+1)dx x∈[0,1]
A=∫3x²dx+∫2xdx+∫dx=(x³+x²+x)l 0↑1=3-0=3
