lim x²(e^1/x-e^1/(x-1))=lim x²/[1/(e^1/x-e^1/(x-1))]=∞/∞ aplici T L Hospital
L=lim2x/[-((e^(1/x)-e^(1/(x-1))/(e^1/x-e^1/(x-1))²]=-lim 2x/1/(e^1/x-e^1/(x-1)=
-∞/∞ aplici in continuare teorema
L=-lim 2/[-(e^1/x-e^1/(x-1))/(e^1/x-e^1/(x-1))²]=lim2/[1/(e^1/x-e^1/(x-1)]=2/[1/0]=
2/∞=0